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Subelement E7

PRACTICAL CIRCUITS

Section E7D

Power supplies and voltage regulators; solar array charge controllers

How does a linear electronic voltage regulator work?

  • It has a ramp voltage as its output
  • It eliminates the need for a pass transistor
  • The control element duty cycle is proportional to the line or load conditions
  • Correct Answer
    The conduction of a control element is varied to maintain a constant output voltage

HINT: voltage regulate = maintain voltage

In electronics, voltage regulators maintain a constant output voltage.

So, whether the question mentions Linear or Switching voltage regulators, choose the answer that mentions maintaining a constant output voltage.

The resistance of the regulator varies in accordance with the load resulting in a constant output voltage.

https://en.wikipedia.org/wiki/Linear_regulator

Hint: Regulator (in question) provides Constant output voltage (in answer)

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How does a switchmode voltage regulator work?

  • By alternating the output between positive and negative voltages
  • Correct Answer
    By varying the duty cycle of pulses input to a filter
  • By varying the conductivity of a pass element
  • By switching between two Zener diode reference voltages

A switchmode voltage regulator switches the source voltage on and off in varying amounts of time. The amount of time it is on vs off is known as the duty cycle. You are then left with a pulsating voltage, so a filter is used to smooth it out.

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What device is used as a stable voltage reference?

  • Correct Answer
    A Zener diode
  • A digital-to-analog converter
  • An SCR
  • An analog-to-digital converter

A Zener diode is typically used as a stable reference voltage in a linear voltage regulator. When reverse biased, the diode breaks down and allows current to flow in the reverse direction when the voltage is above the avalanche point. The Zener voltage is the voltage necessary to cause the avalanche to occur and allow current to flow. As long as the reverse bias voltage remains above the avalanche point, the voltage drop across the Zener diode remains constant to provide a stable reference for regulating power supply output voltage.


Hint: this is a stretch but it worked for me...
stables are for horses
Zorro had a horse
Z is for Zener

A Zener Diode is the simplest type of voltage regulator.


Hint 2: a ZEE-ner is LEEnyer (linear). Weird, but helps me remember.


Remember seeing Varactor somewhere as an answer? Both hint 1 and 2 work as 'stable' and 'linear' are not a part of a different, similar question:

What type of semiconductor device is designed for use as a voltage-controlled capacitor? Varactor diode

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Which of the following describes a three-terminal voltage regulator?

  • A series current source
  • Correct Answer
    A series regulator
  • A shunt regulator
  • A shunt current source

A series voltage regulator, also known as a three-terminal voltage regulator, typically has three terminals:

  1. Unregulated DC input voltage
  2. Regulated output DC voltage
  3. Ground

Tip: Only two answers are regulators, and you "shunt" pick the wrong answer.

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Which of the following types of linear voltage regulator operates by loading the unregulated voltage source?

  • A constant current source
  • A series regulator
  • A shunt current source
  • Correct Answer
    A shunt regulator

An example of a shunt regulator is using a Zener diode in series with a resistor between supply and ground. The Zener diode establishes a constant voltage drop and the resistor sets a constant current.

Note: You can immediately dismiss two of the possible answers. "Regulator" appears in both the question and the answer.

HINT: While performing a carotid endarterectomy, (removing the blockage from the carotid artery), the surgeon must SHUNT the blood around the blockage to have CONSTANT blood flow to the brain.

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What is the purpose of Q1 in the circuit shown in Figure E7-2?

  • It provides negative feedback to improve regulation
  • It provides a constant load for the voltage source
  • Correct Answer
    It controls the current to keep the output voltage constant
  • It provides regulation by switching or “chopping” the input DC voltage

Realize that the transistor Q1, a bipolar junction transistor (BJT), is the valve for current flow and is controlled by the Base current. The Zener diode D1 cannot supply the load with enough current and operate as a reference point.

Q1 increase or amplifies the current-handling capability of the diode supplying current to the Base.

Hint: Only 1 answer with "controls"

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What is the purpose of C2 in the circuit shown in Figure E7-2?

  • Correct Answer
    It bypasses rectifier output ripple around D1
  • It is a brute force filter for the output
  • To prevent self-oscillation
  • To provide fixed DC bias for Q1

If you see closely, C2 is connected in parallel to D1. This will basically act as a filter across D1 and prevent oscillations across D1 and hence prevent the hum.

Remember the term bypass capacitor and that a bypass capacitor will pass above certain wavelengths of AC current while blocking DC current. Bypass capacitors are very common for eliminating undesirable AC current such as noise so it is useful to remember this term.

Hint: C2 is closest to D1 on the schematic, and the correct answer is the only one that references D1.

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What type of circuit is shown in Figure E7-2?

  • Switching voltage regulator
  • Common emitter amplifier
  • Correct Answer
    Linear voltage regulator
  • Common base amplifier

In this question, it is most important to choose the most correct answer-- a linear regulator-- even though an emitter follower is present in the circuit.

D1 is a zener diode; it begins to conduct in reverse when the voltage exceeds a breakdown value. R1 provides current to D1 until this happens. Therefore, the voltage at Q1's base is approximately D1's zener voltage (probably somewhere around 12.7V in this case).

Q1 is an emitter follower that "amplifies" the voltage on its base on its emitter. Together, this entire circuit accepts a high voltage on its input (on the left, 25V) and produces 12V on its output (at right) and thus forms a linear regulator.

TEST TIP: In the top left corner of the diagram you have +25 volts. Follow a straight LINE across, from left to right, and you'll see +12 volts in the top right corner of the diagram. Let that line remind you of LINEAR and then also note the VOLTAGE has been REGULATED down from 25v to 12v = Linear Voltage Regulator.

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How is battery operating time calculated?

  • Average current divided by capacity in amp-hours
  • Average current divided by internal resistance
  • Correct Answer
    Capacity in amp-hours divided by average current
  • Internal resistance divided by average current

Battery capacity is measured in amp-hours; how many amps a battery can deliver in one hour.

Intuitively, if we are given a value in amp-hours and we need to solve for hours, we divide by amps:

(amps*hours)/amps = hours

Example: a 12 amp-hour battery will operate a 4 amp load for 3 hours (12 Ah / 4 A = 3 hours).

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Why is a switching type power supply less expensive and lighter than an equivalent linear power supply?

  • The inverter design does not require an output filter circuit
  • The control circuitry uses less current, therefore smaller heat sinks are required
  • Correct Answer
    The high frequency inverter design uses much smaller transformers and filter components for an equivalent power output
  • It recovers power from the unused portion of the AC cycle, thus using fewer components

Hint: smaller transformer and components = lighter and more often less expensive.

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What is the purpose of an inverter connected to a solar panel output?

  • Reduce AC ripple on the output
  • Maintain voltage with varying illumination levels
  • Prevent discharge when panel is not illuminated
  • Correct Answer
    Convert the panel’s output from DC to AC

An inverter is a device that converts AC to DC. Solar panels only output DC, so an inverter connected to a solar panel is used to convert the output DC into AC.

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What is the dropout voltage of a linear voltage regulator?

  • Minimum input voltage for rated power dissipation
  • Maximum output voltage drop when the input voltage is varied over its specified range
  • Correct Answer
    Minimum input-to-output voltage required to maintain regulation
  • Maximum that the output voltage may decrease at rated load

Linear voltage regulators maintain a constant output voltage in a circuit by using a control element that responds to current. If the "pass element" in a series regulator doesn't receive enough input voltage it can't perform that control function. Consequently output voltage begins to drop below the regulated value.

The minimum voltage a regulator requires before drop out occurs is called the "drop-out voltage."


Hint: A voltage regulator maintains regulation. Only one answer choice has this word.

Another hint: Many students who only do the minimum amount of required work to maintain their grade may eventually dropout.

Hint: dropout + output = dropOUTput

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Which of the following calculates power dissipated by a series linear voltage regulator?

  • Input voltage multiplied by input current
  • Input voltage divided by output current
  • Correct Answer
    Voltage difference from input to output multiplied by output current
  • Output voltage multiplied by output current

Electrical power is measured in Watts and calculated by multiplying the voltage by the current. In an electrical circuit, every device will have either a voltage "drop", i.e. consumes power, such as a resistor, or a "voltage gain", i.e. produces power such as a battery.

A linear voltage regulator is no different in this respect. A linear voltage regulator is explicitly designed to do this in a reliable fashion, by taking a higher (usually unregulated) voltage and producing a lower, regulated voltage.

A power calculation across a regulator can be difficult if the input is highly unregulated, or the current demand of the regulated circuit changes frequently but that's not the point of the question. Power consumption, and in most cases "dissipation", meaning wasted power, is always the voltage drop multiplied by the current through the device.

An example could be a 9-volt battery connected to a 5 volt linear regulator, powering a circuit that consumes 2 amps. Since current is always conserved, the 2 amps at 5 volts going into the powered circuit comes from 2 amps at 9 volts coming from the battery. While the powered circuit would consume 10 Watts

\[P=IV=(2 \text{ A})(5\text{ V})=10 \text{ W}\]

the regulator has to dissipate the excess energy from the 18 Watts

\[P=IV=(9\text{ V})(2 \text{ A})=18 \text{ W}\]

coming from the battery. In this case, you would see 2 amps of current moving through the regulator, with 9 V as its input and 5 V as its output. The regulator would be dissipating 8 Watts.

\[(9 \text{ V} - 5 \text{ V}) \times 2 \text{ A} = 4 \text{ V} \times 2 \text{ A} = 8\text{ W}\]

Linear regulators are specifically designed to do this, but care has to be taken that the heat generated by the regulator is properly dissipated and within the design limits of the regulator.

  • Hint * the correct answer is the only one that has "Voltage" as the first word.

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What is the purpose of connecting equal-value resistors across power supply filter capacitors connected in series?

  • Equalize the voltage across each capacitor
  • Discharge the capacitors when voltage is removed
  • Provide a minimum load on the supply
  • Correct Answer
    All these choices are correct

Answer: All of these choices are correct.

Think of a simple capacitor: it is two plates separated by an insulator. When you connect capacitors in series, you are charging up all of the capacitors with the same number of electrons (the same current flows through each because they are in series).

If the capacitors have any imperfections, they will each end up with a different voltage, and resistors can help balance the capacitors because the fuller ones will have a higher voltage, and therefore get discharged faster by the resistor.

The value of the resistors chosen is high such that the resistance is at least 10 times the highest value of \(X_C\), where

\[X_C = \frac{1}{2πfC}\]


Hint: Equal-value -> Equally important (All these choices are correct)

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What is the purpose of a step-start circuit in a high-voltage power supply?

  • To provide a dual-voltage output for reduced power applications
  • To compensate for variations of the incoming line voltage
  • To prevent arcing across the input power switch or relay contacts
  • Correct Answer
    To allow the filter capacitors to charge gradually

A "step start" circuit gradually increases the voltage applied to filter capacitors. The reason we use this circuit, is to avoid putting the full voltage on the capacitor all at once. If we were to put the full voltage on the capacitor all at once, it might fail (literally blow up), or at least result in a decrease in the capacitor's useful life.

Hint: Gradually

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